Make sure you go through and revise the second lesson of Current Electricity, so that you do better in this test. As this test can be taken only once, and your score will be saved.
Make sure you have a scientific calculator with you before you start, for calculations.
This test will show, how well you are prepared for the exam. So don’t forget to revise before you start.
This mega test includes 30 Current electricity Questions.
Total time for this mega test is 30minutes.
You have 1 minute for each question.
Good Luck!
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Which particles in the wire move to cause this current?
Current is produced from the flow of electrons.
I (in A) = Q (in C) / t (in s) , And Electrons move from negative terminal to the positive terminal.
In an electric circuit, 40C of electric charge pass a point in 5.0 s.
What is the current in the circuit?
I (in A) = Q (in C) / t (in s)
The diagram shows a circuit.
The reading on the ammeter is 12A.
How much charge passes through the ammeter in 2.0 minutes?
Don’t forget to convert the time in minutes to seconds.
1 minute = 60 seconds.
In the circuit shown, the voltmeter reads 2.0 V . A charge of 5.0 C passes through the resistor in a certain time.
How much energy is supplied to the resistor in this time?
Re-arrange the equation, V = E / Q.
Which circuit shows a voltmeter measuring the p.d. across a resistor?
Make sure to select the option that measures potential difference (p.d) across the resistor as told in question (not across lamp).
Potential difference is also referred to as voltage.
Which symbols are used for the units of current and of resistance?
The unit of Resistance is ohms and of current is amperes.
A pupil measures the potential difference across a device and the current in it.
Which calculation gives the resistance of the device?
The circuit shows a 24 V battery connected to two resistors in series.
The reading on the ammeter is 2.0 A and the reading on the voltmeter is 8.0 V.
What is the resistance of resistor R?
R = V / I
A small potential difference V is applied across a filament lamp. The current I in the lamp is measured . V is increased in stages and I is measured at each stage.
Filament lamp is a non-ohmic conductor, means it does not obey Ohm’s law. So current and voltage will not be directly proportional.
The diagram shows a battery connected to two resistors.
Four students separately measure the electromotive force (e.m.f.) of the battery, the current in the resistors, and the potential difference (p.d.) across resistor R.
Their results are shown in the table below.
Which row shows values with their correct units?
Just Look at the units of each quantity carefully.
Which diagram shows the current-voltage (I-V) characteristic for a filament lamp?
Filament lamp is a non-ohmic conductor, As it’s temperature does not remains constant, for the Ohm’s law to obey.
The graph shows the relationship between the current in a circuit component and the potential difference (p.d.) across it.
The graph has a straight section and a curved section.
What happens to the resistance of the component in these two sections as the current increases?
A wire has a certain electrical resistance.
The diameter and length of the wire may be changed.
Which pair of changes must cause the resistance of the wire to increase?
R = pl / A
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
Which two changes to a metal wire both increases resistance?
R = pl / A
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
And temperature is directly related to resistance.
The diagrams represent four copper wires.
Which wire has the greatest resistance?
R = pl / A
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
The diagram shows a piece of metal resistance wire.
Which wire, made of the same metal, has a smaller resistance?
R = pl / A
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
A student has wires of different lengths and different diameters. The wires are all made of the same metal.
The student measures the resistance of one wire.
Which wire has a greater resistance than the wire he has measured?
R = pl / A, resistivity p is same, for same materials.
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
Four wires are made from the same material.
Which wire has the least resistance?
R = pl / A, resistivity p is same, for same materials.
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
No need of calculation, just see the values and apply how they are proportional.
Which sample of copper wire has the greatest electrical resistance?
R = pl / A, resistivity p is same, for same materials.
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
No need of calculation, just see the values and apply how they are proportional.
Which copper wire would have the smallest resistance?
R = pl / A, resistivity p is same, for same materials.
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
A student uses a length of wire as a resistor. He discovers that the resistance of the wire is too small.
To be certain of making a resistor of higher value, he should use a piece of wire that is
R = pl / A, resistivity p is same, for same materials.
Resistance R is directly proportional to the length, and inversely proportional to the cross-sectional area (thickness) or diameter.
The diagram shows an incomplete circuit.
Four wires of different length and thickness are connected in turn between point X and Y.
All four wires are made of the same metal.
Which wire will cause the greatest reading on the ammeter?
R = V / I, shows that Resistance R is inversely proportional to the Current I.
So higher current reading means lower resistance.
Then, R = pl / A
A metal wire of length 100 cm and cross-sectional area 0.20 mm² has a resistance of 8.0?.
What is the resistance of a wire of the same metal of length 50 cm and cross-sectional area of 0.40 mm² ?
Compare the two wires using the equation, R = pl / A.
If not getting how to do it go back and watch the videos again.